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5n^2=6n+32
We move all terms to the left:
5n^2-(6n+32)=0
We get rid of parentheses
5n^2-6n-32=0
a = 5; b = -6; c = -32;
Δ = b2-4ac
Δ = -62-4·5·(-32)
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{676}=26$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-26}{2*5}=\frac{-20}{10} =-2 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+26}{2*5}=\frac{32}{10} =3+1/5 $
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